Euler Problem 6 – Sum square difference

Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

This was simple.

Sum_Square_difference = function(x) {
return(sum(1:x)^2 - sum((1:x) * (1:x)))
}

Sum_Square_difference(10)
[1] 2640
Sum_Square_difference(100)
[1] 25164150
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